Takes a numeric variable (could be of class numeric or integer) and
returns a discretized version, in which each element has been replaced by a
single integer between 1 and nlevels, inclusive.
discretize(x, ...)
# S3 method for numeric
discretize(x, nlevels, method = "equal", ...)
# S3 method for integer
discretize(x, nlevels, ...)
# S3 method for FitLandDF
discretize(x, nlevels, ...)either a vector (numeric or integer) or FitLandDF object
potential additional arguments, currently unnecessary
positive integer indicating number of discrete categories
method by which to discretize; split into equal sections by
default ("equal" value for parameter)
discretized form of x
## discretize a numeric vector
vec <- 1:10
discretize(vec, nlevels = 5) # discretize into 5 categories
#> [1] 1 1 2 2 3 3 4 4 5 5
discretize(vec, 2) # discretize into 2 categories
#> [1] 1 1 1 1 1 2 2 2 2 2
## discretize a fitness landscape
# create a 3x3x3 fitness landscape with values 1 through 27
fl_data <- array(1:27, dim = rep(3, 3))
my_fl <- fitscape::FitLandDF(fl_data)
discretize(my_fl, nlevels = 2) # discretize landscape into 2 categories
#> [1] "A fitness landscape with dimensions 3x3x3 and for which 27 values are known."
discretize(my_fl, 5) # discretize landscape into 5 categories
#> [1] "A fitness landscape with dimensions 3x3x3 and for which 27 values are known."